Saturday, September 27, 2008

Homework due 9/29/08

Do problems on pages 67-68; # 1, 2 and 13.

4 comments:

Anonymous said...

For number two on page 67, there is probably some really simple answer that I am not seeing, but how do you prove that either angle APO = angle OQB or Ao=OB. I figure <1 and <2 being equal have soemthing to do with it, but I am not sure.

Anonymous said...

hey victoria! I think you might be able to prove it by proving that the two triangles are congruent, since that means all corresponding angles are equal. I'm not sure though.

Anonymous said...

actually maybe because they are both supplements of either angle 1 or angle 2 and those are equal, so they have to be.

Anonymous said...

I think you're right about the supplementary angle thing, Virginia. I was looking over the problem and since they only gave you one equal angle and side, you'd either have to prove another angle was equal, which the supplementary angle theorum would do, or prove that XPOQY bisects straight angle AOB, and I'm not really sure how to do that...