Thursday, March 19, 2009

Homework due 03/20/09

Do problems 2, 4, 5, 7 & 9 on page 278.

6 comments:

Anonymous said...

For number 7, can someone refresh my memory on finding the area of a hexagon? I know it has something to do with the triangles...

Anonymous said...

can someone help me with 4? I'm not sure what the altitude of the prism is.

Anonymous said...

never mind i think i got it

Anonymous said...

for 5 and 9, how do you find the heights of the trapezoids and the triangles to find the areas of the bases? maybe i am just forgetting something

Anonymous said...

virginia, for number 9, the height is given, and for number 5, the height is the same as the length of the prism. Hope this helps.

Anonymous said...

For number 7, consider a regular hexagon as consisting of two trapezoids.

As for 5, think of the nature of the trapezoid. It's an isosceles trapezoid and so consider it's height as that of the height of an isosceles triangles height. If you split it then it forms two right triangles.