I don't know if this is how we are supposed to find the area, but I created the altitude of the triangle and then created two sets of equations. One length of the base is 15-x and the other is x. Using the two equations, you can find one variable and then substitude to find x. From there you can find the area. I think that is one way to go about the problem, but I don't how to find the area using trig.
if you drop an altitude, doesn't it form a pair of similar triangles, and you can find the lengths of the base. PS- sorry bout the late reply, I've been afk
8 comments:
i found some ratios but im not sure how to use them to find an angle- can anyone help me?
sin inverse/cos inverse/tan inverse
Care to elaborate Michael?
i just dont know how to use those with out knowing the lengths of the base divided by the altitude- can anyone help me with how to find those?
Michael,
I think I see where you're going,however, do you have any pointers as to finding the length of q? If I could do that, I would be set.
Vranian
I don't know if this is how we are supposed to find the area, but I created the altitude of the triangle and then created two sets of equations. One length of the base is 15-x and the other is x. Using the two equations, you can find one variable and then substitude to find x. From there you can find the area. I think that is one way to go about the problem, but I don't how to find the area using trig.
if you drop an altitude, doesn't it form a pair of similar triangles, and you can find the lengths of the base. PS- sorry bout the late reply, I've been afk
Michael- I thought only right triangles could be split into similar triangles...
I've found some interesting ratios that could possibly be generalized, but I'm not sure how to proceed in the proof...
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